5xy=2x^2+2y^2

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Solution for 5xy=2x^2+2y^2 equation:


Simplifying
5xy = 2x2 + 2y2

Solving
5xy = 2x2 + 2y2

Solving for variable 'x'.

Reorder the terms:
5xy + -2x2 + -2y2 = 2x2 + -2x2 + 2y2 + -2y2

Combine like terms: 2x2 + -2x2 = 0
5xy + -2x2 + -2y2 = 0 + 2y2 + -2y2
5xy + -2x2 + -2y2 = 2y2 + -2y2

Combine like terms: 2y2 + -2y2 = 0
5xy + -2x2 + -2y2 = 0

Factor a trinomial.
(-2x + y)(x + -2y) = 0

Subproblem 1

Set the factor '(-2x + y)' equal to zero and attempt to solve: Simplifying -2x + y = 0 Solving -2x + y = 0 Move all terms containing x to the left, all other terms to the right. Add '-1y' to each side of the equation. -2x + y + -1y = 0 + -1y Combine like terms: y + -1y = 0 -2x + 0 = 0 + -1y -2x = 0 + -1y Remove the zero: -2x = -1y Divide each side by '-2'. x = 0.5y Simplifying x = 0.5y

Subproblem 2

Set the factor '(x + -2y)' equal to zero and attempt to solve: Simplifying x + -2y = 0 Solving x + -2y = 0 Move all terms containing x to the left, all other terms to the right. Add '2y' to each side of the equation. x + -2y + 2y = 0 + 2y Combine like terms: -2y + 2y = 0 x + 0 = 0 + 2y x = 0 + 2y Remove the zero: x = 2y Simplifying x = 2y

Solution

x = {0.5y, 2y}

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